Question:

1/R = 1/R1 1/R2 for R1 ( Electric circuit)

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1/R = 1/R1 1/R2

for R1 ( electric circuit)

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  1. 1/R = 1/R1  + 1/R2

    so  1/R -1/R2 =1/R1

    ( r2 -r )/ (r * r2) =  =1/R1

    now do reciprocal of both sides

    (r * r2) /( r2 -r ) = R1


  2. What is the question?

    Can't help you unless I know what you want to know.

    And you left out a +

    1/R = 1/R1 + 1/R2

    easier to use is

    R = r1*r2/(r1+r2)

    rereading, do you mean "solve for R1"? Adding that word "solve' makes it so much more easier to understand!

    R1 = R*R2/(R-R2)

    .

  3. Well, there's several ways to go about solving for R1

    1/R = 1/R1 + 1/R2  (Substract 1/R2 from both sides of the equation).

    1/R - 1/R2 = 1/R1

    Thus, 1/R1 = 1/R - 1/R2

    Now, you have to find the common denominator for the 1/R - 1/R2.  You will need to cross multiply in order to get:

    1/R1 = ((R2 - R) / (R2 x R))

    Then, you want to invert your equation.

    R1 = ((R2 x R) / (R2 - R))

    ---------------------------------

    Another approach:

    R = ((R1 x R2) / (R1 + R2))

    solving for R1:

    multiply both sides of the equation by (R1 + R2)

    R(R1 + R2) = R1 x R2

    dividing through by R

    (R1 + R2) = (R1 x R2) / R

    substract R2 from both sides:

    R1 = ((R1 x R2) / R) - R2

    find the common denominator for the right side

    R1 = (R1 x R2 - R x R2) / R

    Factor out R2

    R1 = R2 x (R1 - R) / R

    divide both sides by (R1 - R)

    R1 / (R1 - R) = R2 / R

    invert the equation

    (R1 - R) / R1 = R / R2

    then R1 / R1 is just 1

    (R1 / R1) - R / R1 = R / R2

    1 - R / R1 = R / R2

    substract 1 from both sides of the equation.

    -R / R1 = R / R2 - 1

    -R / R1 = (R / R2) - R2 / R2

    then find the common denominator on the right side of the equation.

    -R / R1 = (R - R2) / R2

    cross multiply to get

    R x R2 = R1 x (R - R2)

    solve for R1

    R1 = (R x R2) / (R - R2)

    It's a bit tricky, but there it is.

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