[(1/a)-(1/a+h)] x [(1/a)-(1/a+h)] HELP FOIL!! What is 1/a times 1/a? Havent taken math in years.?

Question

[(1/a)-(1/a+h)] x [(1/a)-(1/a+h)] HELP FOIL!! What is 1/a times 1/a? Havent taken math in years.?

Answer 1

= ([1/a] - [1/{a + h}])([1/a] - [1/{a + h}])

= ([{a + h} - a]/[a{a + h}])([{a + h} - a]/[a{a + h}])

= ([a + h - a]/[a{a + h}])([a + h - a]/[a{a + h}])

= ([a + h][a + h])/([a{a + h}][a{a + h}])

= 1/a²

Answer: 1/(a[a]) or 1/a²

Answer 2

1/a X 1/a = 1/a^2

The answer to the problem is

[1/a^2] - [2/(a^2 +ah)] + [1/(a^2+2ah+h^2)]

AM

Answer 3

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+

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-

hf34hf793hf78f78234fg67g3f63

=

2g8h2378fg78934hf893h2f782fyh78234f247fh...

Answer 4

1/a · 1/a = 1²/a² = 1/a²

Answer 5

this is by using (a-b)^2 formula

a^2 -2ab+b^2

you get

(1/a)^2-2(1/a)(1/a+h)+(1/a+h)^2

=1/a^2 - 2/{a(a+h)} + 1/(a+h)^2

1/a multiplied by 1/a= 1/a^2

Answer 6

h^2