[1-x^2] -[ 2x +1] =?

Question

[1-x^2] -[ 2x +1] =?

Answer 1

[1 - x^2] - [2x + 1]

Distribute the "-" through the second parenthesis and remove the parenthesis:

1 - x^2 - 2x - 1

Rearrange, grouping like terms:

1 - 1 - x^2 - 2x

-x^2 - 2x

Factor out -x:

-x(x + 2)

Answer 2

-x^2 - 2x

Answer 3

=1-x^2-2x-1

=-x(x+2)

Answer 4

(1 - x²) - (2x + 1)

Distribute the middle "-" sign (think of it as an understood -1) over the second term:

1 - x² - 2x - 1

The 1-1 cancels out to 0, so you end up with:

-x² - 2x

You can leave it like that, or you can factor out the common term "-x" to get:

-x(x+2)

-IMP ;) :)

Answer 5

Starting with the second term,

-[2x + 1] = -2x - 1    

because the law of distribution is applicable here and the minus sign distributes over (or applies to) everything inside of the brackets.

There is no problem with the first term [1 - x^2] = 1 - x^2

Combining them you get:

1 - x^2 - 2x - 1

That can be regrouped as follows:

1 - 1 - x^2 - 2x       1 - 1 = 0 so you are left with:

-x^2 - 2x              

That is a perfectly acceptable answer, but you can factor it down to:

-x * [x] - x * [2]       where * is the multiplication symbol.

Since both terms have a common (-x) multiple we finally get:        

[-x] * [x + 2]   <<<<< Final answer