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10 POiNTS TO THE FiRST RiGHT ANSWER! MATH QUESTiON! PROBABiLiTY!?

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A bowl contains 36 green grapes and 14 purple grapes. You randomly choose a grape, eat it, and randomly choose another grape. Find the probability that both grapes were green. Show your work.

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  1. Okay, there are 36 green grapes and 14 purple grapes. All together in the bowl there are 50 grapes. The first time you pick a grape, the chances of you getting a green one are 36/50. Since you ate the grape, there are only 49 left in the bowl. Assuming the first grape was green, that only leaves 35 other green grapes. So in your section selection, the probability of getting a green grape is 35/49. Multiply 36/50 and 35/49, and your answer is 18/35.


  2. Total number of grapes=36+14=50

    Probability that first grape is green: 36/50

    Probability that second grape is green: 35/49 (because you already ate one)

    Probability that both were green: 36/50 * 35/49= 0.514 or 51.4 %

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