10 points for most help?

Question

Starting from rest, a car travels 1350 meters in 60 secs. It accelerates at 1.0 m/s^2 until it reached its cruising speed. Then it drove the remiang distance at constant velocity. What was its cruising speed? Please show work.

Answer 1

lol you should do your own homework

Answer 2

The distance covered by acceleration = 1350m (which has nothing to do with our calculation)

acceleration = 1 m/s/s.

time taken to cover this distance = 60 sec

Initial velocty = 0 m/s

Using first equation of motion

v = u + at = 0 + 1(60)

  = 60 m/s

Answer 3

v (cruising) = 30 m/s

some crazy car!!

plot v-t graph

========== v = t

...................... | --- > -------------------|

u=0 ------ t -------|------ (60 -t) ----------|

distance travelled =area under the graph

let the car accelerate for (t) sec

a = 1 m/s^2 = (v-0)/t

v = t >>>> then cruises with this

1350 = triangle area + rectangle area

1350 = (1/2) t*t + (60-t) * t

2D equ Its solutions are

t =90 s >>>>>>> reject more than time =60

t = 30 s

=================

v = cruising = t = 30 m/s

1350 = (1/2)*900 + 900 = 450+900