Question:

10 points to whoever can help me with calculus intervals???

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show that the equation f(x) = x^3 + x + 6 has at least one solution in the interval [-3, 0]

determine the interval for which f(x) = (1/(sqrt(3-x))) is a continuous function.

btw sqrt is my little abbreviation for square root =P

thanks in advance!

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  1. Unfortunately, I only know how to solve the first one...I'm in calculus, as well.

    f(x) also can mean y, when you're talking about intervals. So...

    0 = (-3)^3 - 3 + 6

    0 = (-3)^3 + 3

    0 = -27 + 3

    0 = -24

    And obviously, it does not. I don't see any solutions here...maybe I'm doing it wrong...but that's what I would put if it was on my homework, anyway...sorry...

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