Question:

100 hp climb angle of 20 degrees. altitude?

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a 2100 lbs airplane requires a power of 100 hp at the propeller to climb at an angle of 20 degrees to the horizontal at constant speed. how much altitude could it gain in 10 minutes.

air resistance ignored

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  1. "air resistance ignored"

    Without air resistance, the propellor won't work, it will just spin around uselessly. So the answer is zero. In fact it will fall.

    But assuming a extreme simplification, and all of the energy of the engine is somehow converted to movement:

    Ignoring the angle, just use the energy and weight to calculate how far that energy can lift that weight.

    100 hp is 74.6 kW

    2100 lb is 953 kg

    953 kg has a weight of 9339 Newtons

    10 minutes is 600 seconds

    74.6 kW x 600s = 44.76 MJ of energy available in those 10 minutes

    that much energy can lift a weight of 9339 Newtons how far

    44.76 MJ = D x 9339 Newtons

    D = 4.79 km or 2.98 miles

    .

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