Question:

10pt for solving alg 2? =]?

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  1. x=-7/3


  2. [ (2x + 5) / (2x + 3) ] = [ (x + 3) / (x - 1) ]

    [ (2x + 5) (x - 1) / (2x + 3) ] = [ (x + 3) ]

    [ (2x² - 2x + 5x - 5) / (2x + 3) ] = [ (x + 3) ]

    [ (2x² + 3x - 5) / (2x + 3) ] = [ (x + 3) ]

    [ (2x² + 3x - 5) ] = [ (x + 3) (2x + 3) ]

    [ (2x² + 3x - 5) ] = [ (2x² + 3x + 6x + 9) ]

    [ (2x² + 3x - 5) ] = [ (2x² + 9x + 9) ]

    2x² + 3x - 5  = 2x² + 9x + 9

    2x² + 3x - 2x² - 9x = 9 + 5

    -6x = 14

    x = 14/-6

    x = -7/3

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