12 golfers/6 rounds/foursomes. Arrange so each plays everyone else at least once.?

Question

12 golfers/6 rounds/foursomes. Arrange so each plays everyone else at least once.?

Answer 1

You could use a combination like this and have everyone play each other at least once, in 4 rounds.

1 4 7 10  <-- Foursomes

2 5 8 11

3 6 9 12



1 5 9 12

2 6 7 10

3 4 8 11



1 6 8 11

2 4 9 12

3 5 7 10



1 2 3 <-- Threesomes

4 5 6

7 8 9

10 11 12

Answer 2

another way is to have everyone paired up with a buddy and they play together each of the first 5 days and the sixth is a bonus.

--------------------group 1----- group 2 ------group 3

--------day 1----1,2,3,4 ----- 5,6,7,8-------- 9,10,11,12

--------day 2----1,2,11,12 --3,4,7,8 ------- 5,6,9,10

--------day 3----1,2,9,10---- 3,4,5,6--------7,8,11,12

--------day 4----1,2,7,8 ----- 3,4,9,10------ 5,6,11,12

--------day 5----1,2,5,6------ 3,4,11,12 ---- 7,8,9,10

--------day 6     choose any combo -4 best in group 1.

next 4 in group 2 and last 4 in the 3rd for example

It's not perfect but it works