Question:

1827 is it divisible by 2,3,4,5,6,9,10?

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1827 is it divisible by 2,3,4,5,6,9,10?

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  1. DO THE MATH ON A CALCULATOR!!!! YOU WILL GET THE ANSWER!!!!!!


  2. i think a need calucator for this one lol

  3. 1+8+2+7 = 18

    so it is divisible by 3 and 9 (because 18 is divisible by 3 and 9)

    1827 is an odd number, so it is not divisible by 2

    1827 ends with 7, so it is not divisible by 5. Only numbers ending with 5 is divisible by 5.

    It is also doesn't end with 0 (zero) so it is not divisible by 10

    the last 2 digit is 27 and not divisible by 4 therefore 1827 is not divisible by 4

    i dont know the rule for number 6

  4. Get a calculator and figure it out.

  5. 1827 ends with 7 so it isn't divisible with even numbers

  6. any larger number is divisible by a smaller number..as long as you remember to use your decimals correctly

  7. Heres a trick to find if any number is divisible by 3. Add up all the digits 1+8+2+7 = 18. 18 is divisible by three!

  8. yes by all

  9. It is evenly divisible by 3 and 9.

  10. It's an odd number, so it's not divisible by 2, 4, 6, or 10.

    It does add up to 9 (add up all the digits) so it is divisible by 3 and 9.

    (Not 6 because 6 is even).

    It doesn't end in 5 or 0 so it's not divisible by 5.

    Oh, you only wanted the easy ones! 7 and 11 are a pain.

  11. just looking at it, i know 9 does, b/c it goes into 1800 evenly and it goes into 27. 10 doesnt and neither does 5 or 2. I dont know about the others just looking at it so ya, break out the calculator

  12. Evenly? If so, 2,3,6,and 10 aren't.

  13. 3 and 9

  14. use a calculator. thanks for the two points.

  15. not 2,3,6,10

  16. 9 and 3

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