1+sec/1-sec = cos+1/cos-1 pls...prove?

Question

1+sec/1-sec = cos+1/cos-1 pls...prove?

Answer 1

(1+sec)/(1-sec) = (1+ 1/ cos) / (1- 1/ cos) = (cos + 1) / ( cos - 1)

  

Answer 2

You are advised that your expression of the question is wrong.

"sec" is meaningless,you must write "sec(angle)" such as sec@.

You may use "@ " as an angle! In addition, you should write

"(1+sec@)/(1-sec@)" instead,because it has quite a different meaning.

Proof: the L.H.S.=

(1+sec@)/(1-sec@)=

(1+1/cos@)/(1-1/cos@)=

(cos@+1)/(cos@-1)=

the R.H.S.

Answer 3

take   (1+ sec) / (1 - sec)

        = (1+1/cos) /  (1-1/cos)  (since sec = 1/cos)

        now take L.C.M and cancel cos in numerator & denominator

             =  (cos+1) / (cos-1)