1st order reaction, SO2Cl2 → SO2 + Cl2, has rate constant 2.20 × 10^-5 s-1 at 593 K. SO2Cl2 left after 2 hours

Question

1st order reaction, SO2Cl2 → SO2 + Cl2, has rate constant 2.20 × 10^-5 s-1 at 593 K. How much SO2Cl2 left after 2 hours?

1. a. 1.00%

2. b. 14.7%

3. c. 85.4%

4. d. 17.1%

how?

Answer 1

k= 1/t lnC0/C

k= 2.2x10-5 s-1

t= 2h = 7200s

If C0=100mol

2.2x10-5 = 1/7200ln100/C

7200*2.2x10-5 = ln100/C

0.1584=ln100/C

0.1584=ln100-lnC

4.45=lnC

C=e^4.45=85.3

Then 85.3%  

100-85.3= 14.7%