Question:

2 algebra problems? plz help 10 pts?

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1. Solve the following equation by first multiplying both sides by an appropriate power of 10 so that the equation contains integers only?

0.8x + 0.9= -1.5

x=?

2.solve

6(x+1.37)= 5x

x=?

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10 ANSWERS


  1. .8x -.9 = =-1.5

    .8x = -2.4

    x * -3

    2.

    6x + 8.22 = 5x

    8.22 = -1x

    -8.22 =x


  2. Simply

    0.8x + 0.9= -1.5

    1

    0.8x -0.9=-1.5

    0.8x=-2.4

    x=-2.4/0.8

    x=-3

    2

    6(x+1.37)=5x

    6x+82.2=5x

    -6x          -6x

    82.2=-1x

    82.2/-1 -1x/-1

    x=-82.2


  3. 1. Multiply everything by the first power of ten, so 10^1 = 10. Basically multiply everything by ten, so you don't have to deal with the decimal point anymore and the numbers will be integers and be easier to deal with.

    x10

    8x + 9 = -15

    8x = -24

    x = -3

    2. First distribute the 6.

    6x + 8.22 = 5x

    Move all the x's to one side.

    x = -8.22

  4. the first one i got x= -3

    second one....wasnt sure.

    sorry

  5. for the first ..

    when multiplied by 10 it becomes:

    8x + 9 = -15

    8x = -24

    x = -3

    or -0.3

    And for the second...

    6x + 8.22 = 5 x

    8.22 = -x

    x = -8.22


  6. 1. multiply by 100 and get

    80x + 90 = -150

    x = -3

    2.

    6x + 8.22 = 5x

    x = -8.22

  7. The first answer is -3.

  8. first one, minus 0.9 from itself and from -1.5  

    youll get 0.8x= ____ <-the difference of -1.5-0.9

    then divide by 0.8 from both sides to cancel out the 0.8

    x= whatever the difference of -1.5-0.9 / 0.8

    2nd one..

    6(x) = 6x+ 6(1.37)=5x ..  

    6x+7.37=5x

    minus 6 x from both sides

    7.37=-x

    divide by -1x on both sides

    x=-7.37

  9. 1. x= -3


  10. 1)  10(0.8x+0.9) = 10(-1.5)

          8x+9 = -15

          8x = -15-9

          8x = -24

            x= -3

    2)  6(x+1.37) = 5x

         6x+8.22=5x

         6x-5x = -8.22

           x=-8.22

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