2 bats man each on 94.7 runs to win in 3 balls.both make unbeaten 100.how?

Question

2 bats man each on 94.7 runs to win in 3 balls.both make unbeaten 100.how?

Answer 1

Its got me buggerd how the .7 got into the score, so i take it they are both on 94, The batsman facing hits a 6, stays in crease, next delivery runs a single hes on 101 now, The runner is now facing hits a 6 and scores a century

Answer 2

old question repeated

Answer 3

7 runs to win in 3 deliveries and both batsman A & B at the crease on 94 runs each.

And both made unbeatan centuries. How? This may be the story.....

On the third last delivery or the second last delivery batsman 'A' hits the ball towards the boundery and both batsman runs hard, fielder at the boundery line stops the ball and throws it wildly at the bowlers end and gave away 4 overthrows,Meanwhile batsman has completed 3 runs so in total 7 runs scored by batsman 'A' but the umpirer declares 1 run short, so now batsman 'A' has added 6 runs and completes his century. Now scores are level and 1 run required to win the match. More importantlly batsman 'B' was on strike.  On the last delivery batsman 'B'  hit a six and completes his century.      

Answer 4

The first batsman runs and score 4 by running. In the ovewrthrow he has another run. Then he has a single. He reaches his hundred. And the next batsan hits a six.

Answer 5

Crazy question ... I wonder which two batsman would do so.

Answer is:

○ Actually the both were on 99 and one takes the single and the other also follows. The scorer may have made a mistake.

Because there is no other answer since it states 3 balls. The target needs to be 9 runs to be achieved in 3 balls.

Answer 6

A batsman can only have a non-negative integer number of runs in an innings. They can not have a decimal number like 94.7. I suggest you start putting spaces after fullstops.

Answer 7

Batsman on strike, hit the ball and run for three (second run short of crease) and there is a overthrow for 4. So the batsmen exchange the crease for a total of 6 runs ( 1 run reduced because of short of crease). First batsman reaches 100. Next batsman hit the second ball for 6. Both 100 and match won with a ball to spare.

Answer 8

it is fluke method

one batsman hit a ball and ball hits helmet he gets 5 reaches 99

takes a single on next ball reaches 100

third ball one run remoaning

changed batsman  on crease hits sixer thus completin 100

Answer 9

simple...

batsman hits for six and complete his 100

den next ball up in the air n caught in long off and on strike batsmen crossed, so last ball he hits for 6 and complete his 100.

Answer 10

the batsmen has to try to hit the helmet of the wicket keeper if it is on the ground. Then alos has to take a single. then the other player can hit a six.

ig the helmet is on keeper's head, the batsmen has to force an overthrow and take a single.

Itz simple.