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2 charges have a force of repulsion of 0.80N between them,?

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when they are placed 4.0cm apart. What is the magnitude of the new force when they are moved to a seperation of 10.0cm?

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  1. Electrostatic force is proportional to the inverse square of distance. Multiplying separation by 2.5 decreases force by a factor of 2.5^2.

    F = 0.8/2.5^2 = 0.128 N.

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