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2 cos of theta + 1 = 0, where 0 < or = theta < 3 pi over 2?

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2 cos of theta + 1 = 0, where 0 < or = theta < 3 pi over 2?

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  1. 2 cos of theta + 1 = 0

    cos theta = - 1/2

    theta must be in 2nd or 3rd quadrant

    so theta = 2pi/3 or 4pi/3

You're reading: 2 cos of theta + 1 = 0, where 0 < or = theta < 3 pi over 2?

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