2 pipes take x mints&(x+3)mints respectively to fill a cistern.if together they fill the cistern in 3 1/13 min

Question

2 pipes take x mints&(x+3)mints respectively to fill a cistern.if together they fill the cistern in 3 1/13 min

Answer 1

Given that 1st pipe takes x min

and 2nd pipe takes (x+3) min

Assuming that the volume of the cistern be 'V', we know that sum of all total volumes filled per total time by each tap is equal to V/(3 1/13) or V/(40/13)  or 13V/40.

Therefore  V/x + V/(x+3) = 13V/40

                   1/x + 1/(x+3) = 13/40

On simplification, we've

=>               (x+3 + x)/x^2+3x = 13/40

=>                (2x+3)40 = 13(x^2+3x)

Hereon I hope you can solve it for I don't wish to give every step and stop your brain from thinking!

Answer 2

do you mean X min and (X+3)min?

Answer 3

x+x+3=40/13

2x+3=40/13

2x+3=3.08

2x=3.08-3

2x=0.08

x=0.04 minutes!!!