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2 planes leave port at 1pm.How many mi. apart will they be at 3,if 1 goes north at 150 &other gos west-200mph?

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  1. the distance will be the hypotenuse of a right angled triangle so use pythagoras

    distance ^2 = 300^2 + 400^2 =90000 + 160000

    dist = √250000 = 500mi

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