(2/x-y)-(3/x+y)=? ?

Question

(2/x-y)-(3/x+y)=? ?

Answer 1

This is a simple subtraction problem.  Just take the parenthesis off, distribute the negative in front of the second term and combine like terms.

(2/x-y) - (3/x + y) = 2/x - y - 3/x - y = -1/x -2y

Answer 2

This problem is really simple if I am seeing it correctly.

(2/x-y)-(3/x+y)

First factor the negative sign through the 2nd half and you and just simply add and subtract

2/x - y - 3/x - y

2/x - 3/x - 2y

-1/x - 2y

Answer 3

Assuming 2/(x-y)-3/(x+y)=(2(x+y)-3(x-y))/((x+y)(x...

                                    =(2x+2y-3x+3y)/((x+y)(x-y))

                                    =(-x+5y)/((x+y)(x-y))

Answer 4

(2x+2y)/(x²-y²) - (3x-3y)/(x²-y²) = (5y-x)/(x²-y²)

Answer 5

={(2x+2y) - (3x-3y)}/(x^2-y^2)

= {(2x + 2y) + (-3x + 3y)}/(x^2 - y^2)

=(-x + 5y)/(x^2 - y^2)