2003 Super bowl math problem?

Question

The 2003 super Bowl was played between the Tampa Bay Buccaneers and the Oakland Raiders. The Buccaneers rushed for 90 more yards than the Raiders. The total yards rushed by both teams was 560. How many yards did the Raiders rush for?

anybody get this?

Answer 1

Buccanneers: 560/2+45= 325

Raiders:        560/2-45=235

325-235=90

325+235=560

Answer 2

B= Buccaneers R= Raiders

Rush

B= R+90   B+R= 560

Problem:

B+R=560

(R+90)+ R= 560  (put in new equation for B)

2R +90= 560

2R= 470

R= 235

So the Raiders Rushed for 235 yards.

Answer 3

lets say that :

The Oak. yards = x

then The Buc. = x +90

as the question:

(the oak) + (the Buc.) = 560

x + x +90 = 560

2x = 560-90

2x = 470

x = 235

now replace again :

The Oak. did 235 yards

so The Buc. did 235 +90 = 325 yards.

thanks lol .