Question:

2^3/10^(-2) -2/7^(-2) ?

by  |  earlier

0 LIKES UnLike

I need help!!!

 Tags:

   Report

2 ANSWERS


  1. the way you wrote it down makes it hard to read...

    maybe a hint will help you:

    if you have a negative exponent, the value of the expression stays the same if you use the reciprocal value with the positive exponent

    x°(-2) = 1 / x°2


  2. I think you are trying to subtract these two fractions.  When you have a base with a negative exponent move it to the other side of the fraction and make the exponent positive.  For instance, x^(-6) = 1/x^6 and 1/x^(-5) = x^5.  In your case,

    [2³/10^(-2)] - [2/7^(-2)] =

    [2³*10²] - [2*7²] =  

    2(2²*10² - 7²) =

    2(2*2*10*10 - 7*7) =

    2(4*100 - 49) =

    2(400 - 49) =

    2*351 =

    702

    Hope this helps you!

Question Stats

Latest activity: earlier.
This question has 2 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.