2x^2+2x-2=? i don't know hot to do this please tell me how and explain i did know i just forgot ?

Question

after the upwards arrow that is supposed to be an x squared and what is this math called

Answer 1

You can factor out a 2...

= 2(x^2 + x - 1)

This cannot be factored an more.

This is a quadritic function and what we did was factoring.

Answer 2

take two common and using delta=b^2-4ac, u get solution of this equation. this is the method to solving quardratic equation f(x)=0.

Answer 3

their called powers/ exponents

Answer 4

I plugged it into the quadratic equation and found x to equal [-1 +/- (sq rt5)]/2.

Some of the answers above are incorrect.

X does not equal -8 or 4.

This would mean that (x+8)(x-4)=2x^2+2x-2.

In fact, (x+8)(x-4)=x^2-4x-32, which is NOT the original equation.

Further more, (2x-1)(x-2) is also incorrect.

(2x-1)(x-2)=2x^2-5x+2, which is also NOT the original equation.

Hope I helped.

:)

Answer 5

This is called an exponential equation. They're normally used to solve quadratic equations. To solve it, you make the equation equal to zero, factor it, and then solve both expressions separately. Since this can't be easily factored, you have to do the quadratic equation of which you should look up on wikipedia because it is too hard to show you here.

Answer 6

The equation looks like part of a quadratic. However, you didn't tell us what it equals to, so it's going to be tough for us to help you.

Did you mean 2x^2 + 2x - 2 = 0? If so, the simplest algorithm to follow is most likely the quadratic formula. Suppose your equation is written in terms of ax^2 + bx + c = 0, then the solutions for x are:

-b +/- sqrt(b^2 - 4ac).

Here, you'll notice that we have a = 2, b = 2, c = -2.

Thus, the solutions for x are:

-2 +/- sqrt(4 - 4*2*(-4))

-2 +/- sqrt(4 + 32)

-2 +/- sqrt(36)

-2 +/- 6

-2 - 6 and -2 + 6

x = -8, 4.

Answer 7

it is algebra

2x^2+2x-2----> first  you factor out the two and get

x^2 +x - 1 =0----> now you factor this equation by using the quadratic formula.

a = 1 b=1 c=-1

x =  -1+/- sq rt( 1 -4*1* -1)/2

x =  [-1 +/- sq rt(5)]/2

Answer 8

2x^2 + 2x - 2

= 2(x^2 + x - 1) (<== factorization)

Answer 9

If ? is 0, then it is a Quadratic Equation. Use the Quadratic Formula where a = 2, b = 2, c = -2.

x =[-b ± √(b² - 4ac)] / 2a

x = [-2 ± √(2² - 4(2)(-2))] / 2(2)

x = [-2 ± √(4 + 16)] / 4

x = (-2 ± √20) / 4

x = -2 + 4.472 / 4

x = 2.472 / 4

x = 0.618

x = -2 - 4.472 / 4

x = -6.472 / 4

x = -1.618

Solution set:

x{0.618, -1.618}

¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Answer 10

exponentiation

2x^2 + 2x + 2 =

2(x^2 + x  + 1) =

2(x+1)^2 - 2x =

2[(x+1)^2 -x]

Answer 11

It is difficult to understad what you mean, but looking at the expresion, I would say it is a polinomian multiplication, comming from (a+b) (a-b), which is equal to the square of the first term, plus twice the first term times the second, plus the square of the second term, if I remember correctly.

Multiply term by term, remembering:

+ x + = positive (friend of friend, friend)

+ x - = negative (friend of enemy, enemy)

- x - = positive (enemy of enemy, friend)

+ x - = negative (friend of enemy, enemy)

Good luck.

Answer 12

It's called completeing the square or backwards FOIL or something.

You would seperate it into

(2x-1)(x-2)

The first terms are 2x and x since x times 2x is 2x^2.

For the second part, you use the multiples of the second term in the original equation (in this case 2x) that add or subtract to equal the third term (-2).

For the sign, you know that their both going to be negative since the last one is negative.

To check your work, just FOIL out your answer. (2x-1) times (x-2)

=)