3/7 = - log x how do i find x?

Question

ok - if i have 3/7 = - log x how do i find x?

thanks so much!

and can you please explain how you do it?

thanks!

Answer 1

You can write this as

log x = -3/7

x = 10 ^(-3/7)

Use a calculator to find 10 raised to the power -(3/7) or -(0.42857)

=0.372759372031494

Answer 2

let's say that loga = b

that means 10 raised to the b = a

in this case 3/7 = -logx

so -3/7 = logx

this means 10 raised to -3/7 =x

x = .372759372...

Answer 3

-3/7 = log x => x = 10^ (-3/7) <=>

x= 1 / [10^ 3/7] <=>

x = 1/ ((10^3) )^ (1/7)

what  i mean is that x = 1 / radical  of  7th grade of 10^3

10^3 = 1000.

i hope you understand.

the base of log is 10, not e.

e is the base of ln.  

Answer 4

if b^y = x then y = log b(x)  [log base b of x]

your log is implicitly base ten so...

10^-(3/7) = x = .373