34 cm^3 of CH3COOH is put into 200 ml of solution. Calculate the molarity of the solution.

Question

density of CH3COOH : 1.049 g/cm^3

The acetic acid is in the liquid state.

Molarity = moles solute / liter solution

Answer 1

34 cc = 34 mL =34 X 1.049grams/mL = 35.67 grams

molar mass of acetic acid = 60grams/mole so 35.67 grams = 35.67 /60 grams /mol = 0.594 mole

M = mole /liter  soo 0.594 moles /0.2 liters = 2.972 M

Check  

2.972 M = 2.972 moles /liter = 2.972 X 60 gramsmole = 178.32grams /liter = 35.67 grams/200 mL