4/12.46 – Physics Help Please! Gas and pV trajectory *Hard Problem*?

Question

Please refer to image: http://session.masteringphysics.com/problemAsset/1036217/3/jfk.Figure.P12.46.jpg

A) A gas following the pV trajectory of the figure does 60J of work per cycle. What is P(max)? =???kPa

Answer 1

Deja vu? I already ansvered this... hmm...

Work is equal to p*dV integral - that means the area enclosed by the pV triangle - so the area is .6*(x-100)=60, from the picture. you see that x=200, so it's 200kPa.