4/12.68 – Physics Help Please! Gas undergoing a process *Hard Problem*?

Question

Please refer to image: http://session.masteringphysics.com/problemAsset/1014110/7/jfk.Figure.P12.68.jpg

0.10mol of gas undergoes the isothermal process shown in the figure.

A) What are the temparatures T1 and T2? (T1=???K, T2=???K)

B) The gas undergoes constant-volume heating from point 2 until the pressure is restored to the value it had at point 1. What is the final temperature of the gas? Tf = ???C

Answer 1

ideal gas holds: pV=nRT, so if pV/nR=T=3*101.325*1/(.1*8.314) = 365.6K (it's isothermic, so T1 = T2).

again, pV=nRT, so pV/nR = 3*101.325*3/(.1*8.314) = 1097K.