4 power x+1 is equal to 2 power y+2 then 3 power x-1 is equal to 5 power y-2 then x=? and y=? ?

Question

help me plzzzzzzzz+

Answer 1

HAHAHAHAHAHAH i done this today in maths.

too bad i didnt listen :(

sorry  

Answer 2

x=1 and y=2...substitute the values and check it out

Answer 3

after solving i got x=1,y=2

Answer 4

Im not sure but i think u have to take log on both sides and then differentiate or something

uh.. i hate math

Answer 5

4^2 (x + 1) = 2^(y+2)

so 2^(2x+2) = 2^(y+2)

2x + 2 = y+2 or 2x = y

3^(x-1) = 5^(y-2)

take log of both sides

(x -1) log 3 = (y-2) log 5

put y = 2x to get

(x-1) log 3 = 2( x-1) log 5

is true only is (x-1) = 0 or x= 1 and so y = 2

math kp

Answer 6

4^(x+1)=2^(y+2)

(x+1) ln(4) = (y+2) ln(2)

x ln (4) + ln (4) = y ln (2) + 2 ln (2)

x ln (4) - y ln (2) = 2 ln (2) - ln (4) ---- (1)

3^(x-1)=5^(y-2)

(x+1) ln (3) = (y-2) ln(5)

x ln (3) + ln (3) = y ln (5) - 2 ln (5)

x ln (3) - y ln (5) = - 2ln (5) - ln (3) --- (2)

Solve (1) and (2) for x and y

x ln (4) - y ln (2) = 2 ln (2) - ln (4) ---- (1)

x ln (3) - y ln (5) = - 2ln (5) - ln (3) --- (2)

ln(2)=0.6931471805599453

ln(4)=1.3862943611198905

ln(5)=1.6094379124341002

ln(3)=1.0986122886681097

1.38629 x - 0.69315 y = 0 --- (1)

1.09861 x - 1.609437 y = -4.3174881 --- (2)

x=2.0363

y=4.0726

Answer 7

4^[x+1]=2^[y+2]                                    

=>2[x+1]=y+2

=>2x-y=0

3^[x-1]=5^[y-2] =>  3^[x-1]=5^[2x-2]

[x-1]log3=2[x-1]log5

log 3=2 log 5

it is impossible as log3<log 5

so in the second eqn we shud equate both to 1

then we get x=1 y=2

Answer 8

its answer should be x=1 & y=2