(4y-3)-(4-y)=3y+9......i need HELP please HELP its HARD?

Question

(4y-3)-(4-y)=3y+9......i need HELP please HELP its HARD?

Answer 1

4y^2-21y= -3

Answer 2

4y-3-4+1y=3y+9

add like terms

5y-7=3y+9

add a -3y to both sides

5y-3y-7=9

2y-7=9

add positive 7 to both sides

2y=9+7

2y=16

divide by 2because you want y by itself

y=16/2

y= 8

Check it by substituting the y for the 8.

Answer 3

4y - 3 - 4 + y = 3y + 9

5y - 7 = 3y + 9

2y = 16

y = 8

Answer 4

Well, distribute first.

It would look like this: 4y-3-4+y=3y+9

Then, add your like variables.

It would look like this: 5y-7=3y+9

Subtract the variable: 2y-7=9

Add the -7: 2y=16

Divide the 2: 16/2=8

Therefore, y=8.   ^.^