50.(3a+b)(7a-2b) for a=5 and b =7?

Question

53.81-2{5(n+4)} for n=3

56.b=6and h=14

59.b=16andh=5

62.h=9,b1=12 andb2=16

65.h=,18,b1=6 and b2=11

71.insert parentheses so that 36+12/3+3+6*2 is equal to 50.

Answer 1

50. a = 5 and b = 7

(3a + b)(7a - 2b) =

(3*5 + 7)(7*5 - 2*7) =

(15 + 7)(35 - 14) =

(22)(21) =

462

53.  n = 3  For this problem start with the innermost parentheses and work out.

81 - 2{5(n+4)} =

81 - 2{5(3+4)} =

81 - 2{5(7)} =

81 - 2{35} =

81 - 70 =

11

For questions 56 - 65 I'm not sure what you want to compute since there is no equation provided with these variables.

71.insert parentheses so that 36+12/3+3+6*2 is equal to 50.

{[(36+12)/3]+3+6}*2 = 50

Hope this helps you!