Question:

5(a^b)*(x/a) = 2.5(x)^2

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5(a^b)*(x/a) = 2.5(x)^2

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  1. first step 2.5(x)^2-(a^b)*(x/a)  =0

    factor out a x

    x(2.5x -a^b/a^1 ) =0

    so we already know by the zero property that x=0

    2.5x -a^(b-1) =0

    2.5x = a^(b-1)

    x = a^(b-1) /2.5

You're reading: 5(a^b)*(x/a) = 2.5(x)^2

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