5(x - 3) + 4(x + 3) = 3(x - 1)?

Question

Solve for x.

Answer 1

You use the distributive property.

So after you distribute what is outside of the paranthases to what is inside it is:

5x-15+4x+12= 3x-3

Combine like terms:

9x-3= 3x-3

Get the variables on the same side, so take 3x away from 9x:

6x-3=3

Get the 6x by itself by adding 3 from the left side to the right.

6x=6

Get x by itself by dividing by 6 on each side.

6x/6=6/6

So x=1!

Answer 2

Hi,

For this question, we need to distribute the coefficients over each grouping of terms to get the following:

5x - 15 + 4x + 12 = 3x - 3

Now, simplify both sides of the equation to get:

9x - 3 = 3x - 3

Notice on both sides of the equation a common factor of 3 exists which can be divided out to get:

3x - 1 = x - 1

Now, add 1 to both sides to get:

3x = x

Subtract x from both sides to get:

2x = 0

Divide both sides by 2 to get:

x = 0 <==FINAL ANSWER

I hope that helps you out!  Please let me know if you have any other questions!

Answer 3

5x-15+4x+12=3x-3

5x+4x-3x=15-3-12

6x=0

x=0/6

x=0

Answer 4

5x-15+4x+12=3x-3 then you add like terms on the left side which would give you 9x-3=3x-3 then you add the three to both sides which would give you 9x=3x+0 then you subtract the 3x from both sides which would give you 6x=0 then divide by six on both sides and your answer is x=0. The person above me is wrong.

Answer 5

5(x-3)+4(x+3)=3(x-1)

5x-15+4x+12=3x-3

9x-3=3x-3

9x-3x=3-3

9x=0

x=0

Answer 6

5(x-3) + 4(x + 3) = 3(x-1)

5x- 15 + 4x +12 = 3x -3

5x+4x-3x = 15-12-3

6x = 0

x = 0