Question:

6all over 9 i=?????? help please

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or help on this question 7i x 8i=?????????

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  1. 7i x 8i = 56i


  2. The problem with 6/(9i) (assuming the i to be in the denominator) is that you aren't allowed to have an imaginary in the denominator.  (It's a special case of the "no roots in the denominator" rule.)  First, reduce it to

    2/(3i)

    Then multiply by i/i:

    2i/(3i^2) = -2i/3

  3. Jessie, actually that's incorrect.

    7i x 8i = 56i^2 = 56 x -1 = -56

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