Question:

7(3 - x) = 8(4 - 2x)?

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Solve for x

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  1. 7(3-x)=8(4-2x)

    21-7x=32-16x

    9x=53

    x=53/9


  2. 7(3-x)=8(4-2x)

    21-7x=32-16x

    16x-7x=32-21

    9x=11

    x=9/11

  3. 21 - 7x = 32 - 16x

    9x = 11

    x = 11/9

  4. In case you want them, I am going to put in every step.

    First multiply out the two sides of the equation.

    21 - 7x = 32 - 16x    

    Move the x terms to the left hand side of the equation

    21 - 7x + 16x = 32    

    Move the constant terms to the right hand side of the equation.

    - 7x + 16x = 32 - 21

    Combine like terms

    9x = 11

    Divide both sides of the equation by 9

    x = 11/9  <<<<<

  5. 21-7x=32-16x then subtract 21 from both sides which gives you -7x=11-16x then add 16x to both sides and you get 9x=11 then you divide the nine from both sides and your answer would be x=11/9

  6. Open up brackets first:

    21 - 7x = 32 - 16x

    Put x's on one side:

    21 - 7x + 16x = 32

    -7x + 16x = 32 - 21

    9x = 11

    x = 11/9

  7. multiply 7 with each part inside parentheses

    do the same for the other side of the equal side with 8

    move x's to one side and numbers to the other

    make x stand alone dividing the number side by the x-number

  8. Hi,

    For this question, we have to distribute the coefficients over the respective factors to get:

    21 - 7x = 32 - 16x

    Now, add 16x to both sides to get:

    21 + 9x = 32

    Now, subtract 21 from both sides to get:

    9x = 11

    At this point, we need x alone which is done by dividing both sides by 9 to get:

    x = 11 / 9 <=== FINAL ANSWER

    I hope that helps you out!  Please let me know if you have any other questions!

  9. 21-7x=32-16x

    => 9x=11 => x=11/9

  10. 21-7x=32-16x

    +16x from both sides

    21+9x=32

    -21 from both sides

    9x=11

    x = 11/9
You're reading: 7(3 - x) = 8(4 - 2x)?

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