Question:

7x-5+3>9 PLEASE HELP ME UNDERSTAND?

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Please I dont get these can you help me please so i can understand them

1. 7x-5+3>9

a. x>6

b. x<6

c. x>3

d.x<3

2. sqrt9x^2y^6

3. (6y^2+4y-3)+(3y^2+2)

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4 ANSWERS


  1. 1. 7x-5+3&gt;9

    Isolate the x and if you divide through by a negative number flip the &lt; or &gt;

    7x-5+3&gt;9

    7x&gt;9+5-3

    x &gt;11/7

    none of the multiple choice answers are right. Are you sure you copied it down right?

    2. sqrt9x^2y^6

    the SQRT of X can also be expressed as X^1/2

    (9x^2 y^6)^1/2 = 3x*y^3

    3. (6y^2+4y-3)+(3y^2+2)

    take the sum of like terms

    (6y^2+4y-3)+(3y^2+2) = 9y^2+4y-1


  2. 1. 7x-5+3&gt;9

    Treat this like a regular equation. Isolate the variable on one side by combining like terms.

    7x - 5 + 3 &gt; 9

    7x - 2 &gt; 9

    7x - 2 + 2 &gt; 9 + 2

    7x &gt; 11

    7x/7 &gt; 11/7

    x &gt; 11/7

    There is no answer that matches, please confirm you typed your problem accurately.

    a. x&gt;6

    b. x&lt;6

    c. x&gt;3

    d.x&lt;3

    2. sqrt9x^2y^6

    Is this √(9x²y^6) ? If so:

    Is the same as √(3 × 3 × x × x × y³ × y³)

    3xy² ← Answer

    3. (6y^2+4y-3)+(3y^2+2)

    Combine like terms:

    6y² + 4y - 3 + 3y² + 2

    9y² + 4y - 1 ← Answer

  3. 1)

    7x-5+3&gt;9

    7x-2&gt;9

    7x&gt;11

    x&gt;11/7

    Therefore b and d are correct

    2)3xy^3

    3)6y^2+4y-3+3y^2+2

    (6+3)y^2+4y-3+2

    9y2+4y-1

  4. 1)

    7x - 5 + 3 &gt; 9

    7x &gt; 9 + 5 - 3

    7x &gt; 11

    x &gt; 11/7

    2)

    ±√(9x^2y^6)

    = ±√(3xy^3 * 3xy^3)

    = ±3xy^3

    3)

    (6y^2 + 4y - 3) + (3y^2 + 2)

    = 6y^2 + 4y - 3 + 3y^2 + 2

    = 6y^2 + 3y^2 + 4y - 3 + 2

    = 9y^2 + 4y - 1

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