8.00L sample of oxygen has pressure of 760 mm Hg.?

Question

When volume is reduced to 4.00 liters at constant temp., it will have new pressure of what?

Answer 1

By Boyle's Law of gases, at constant temperature we have

P1V1= P2V2

so, 8*760 = 4*P2

therfore, P2 = (8*760)/4 = 1520 mm. of Hg

Answer 2

V1P1 = V2P2

soo V1 = 8 liters P1 = 1 atm   V2 = 4 liters P2 =

P2 = ( 8liters X 1atm)  /4liters = 2 atmospheres  =1520 mm Hg

Answer 3

Pressure/ volume relationship is easy. If you halve the volume, you double the pressure. So the new pressure will be 1520mm Hg

If you want the maths:

P1V1 =P2V2

760*8 = P2*4

P2 = 760*8/4

P2 = 760*2

P2=1520mmHg