9x-5/6x^2-10x-4 + 3x+7/3x^2-11x-4 (/=fraction)?

Question

9x-5/6x^2-10x-4 + 3x+7/3x^2-11x-4 (/=fraction)

Answer 1

You have to factor the denominators then find a common denominator. I'll factor the first fraction for you:

6x^2 - 10x - 4

=2(3x^2 - 5x - 2)

=2(3x + 1)(x - 2)

So, your first fraction would now be:

9x - 5

----------------------

2(3x+1)(x-2)

Do the same with the second fraction, find your common denominator then solve.