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A 0.5 gram Oxygen gas behaves ideally, how do you find the volume of this gas, when the pressure is 1000torr

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and the temperature is 27C?

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  1. PV = nRT,

    convert 27 C to Kelvin and 0.5 grams to moles and substitute everything in.


  2. PV - nRT

    V = nRT/P

    1000 torr = 1.3158 atm

    27 C = 300 K

    0.5 g = 0.01562 mol

    V = 0.01562x0.08206x300/1.3158 = 0.292 L (292 mL)

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