A 1.00-mole of neon gas occupies 24.4 liters @ 298 K & 101.3 kilo pascals...

Question

Calculate the density of this sample. Include BOTH a correct numerical setup and calculated result.

I got this from the June 2007 Chem regents, #63. Please help!

Answer 1

You've got some information which is not necessary and some is not given. All you need is the volume, but you also need the molecular weight (20.786).

Density = wt./volume =20.786/24.4 = 0.852 g/L

Answer 2

pressure = 101300 / 101325 =1.00 atm

density = atomic mass x p / RT =

20.1797 g/mol x 1.00 atm / 0.0821 x 298 K= 0.825 g/L