A 10.0- resistor, 20.0- resistor, and a 25.0- resistor are connectied in series across the 110-V supply.?

Question

Calculate the answer.

A. 2.0 A

B. 4.5 A

C. 55 A

D. 11 A

Anyone know how to do this? I have no clue whatsoever and I bet it's really easy. As always thansfor the help in advance. :)

Answer 1

A. 2.0 amps would flow.

total resistance = 10+20+25 = 55

current = 110/55 = 2

remember V=IR    or    I=V/R

Answer 2

add up the resistore and you get 55 ohms.

110/55

2 Amps

Answer 3

your question makes no sense. I'm doing GCSE electronics so I thought I could help you, but no chance mate

Answer 4

a I=V/R

Answer 5

you need to calculate the equivalent resistance of the 3 resistors together.

In series, this rule R(total) = R1 + R2 + R3, so it comes to 55 Ohms. now that you have the total resistance, all you need to do is use Ohm's law.

Current = Voltage/Resistance.

              = 110V/55Ohms

              = 2.0 A