Question:

A 2.5cm diameter by 25cm rod. Rod is placed tension force 110kN, it elongates by 0.025cm. what strain in rod?

by  |  earlier

0 LIKES UnLike

How do you solve it?

 Tags:

   Report

1 ANSWERS


  1. 0.025 cm / 25 cm

    epsilon = 0.001 or 0.1%

Question Stats

Latest activity: earlier.
This question has 1 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.
Unanswered Questions