Question:

A 20kg object was dragged along a 5m distance. What was the force exerted?

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A 20kg object was dragged along a 5m distance. What was the force exerted?

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  1. Well, if it was dragged on a horizontal surface on Earth., 196N (or 200N  to 1 significant figure) was exerted vertically  The horizontal force would be 200N x the coefficient of friction (which was not given)

    Of course that is assuming it took forever (to one significant figure) to drag it, since we are not given the time it took I have not bothered with the force required for horizontal acceleration, which could be a bit complicated. (and anyway, we were not told the speed changed)

    If you wanted to know the work done the distance is important, but you didn't ask for the work.


  2. i need the time taken for it to be dragged from 0 point to 5 m....

  3. Using the formula Force = Mass * Acceleration, we need the time taken for the object to travel 5m. then we can work out its acceleration and ultimately the force required.

  4. It depends on the frictional coefficient of the surface it is being dragged across. If the coefficient is 0, the force needed to drag it would be 0 (assuming there aren't any other factors such as wind). If you know the coefficient, the force needed to move it would be greater than (frictional coefficient x weight).

    If you're just looking for the force, the distance it is moved is irrelevant. Distance only comes into play if you are looking for the work done.

    In other words, you can't really work it out without other contributing factors.

  5. tell me the factor causing frtiction or probably the friction coefficient an d i'll tell u this thing ion no matter of time

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