A 22.5 g. sample of ammonium carbonate contains _____ mol of ammonium ions.?

Question

A.) 0.468

B.) 0.228

C.) 0.234

D.) 2.14

E.) 3.47

I think the answer is C, but I wanted to get a second opinion or maybe more opinions....

THANK YOU!

Answer 1

the question asked is how many ammonium ions (NH4)2 are in a sample of 22.5g of ammonium carbonate (NH4)2CO3?

The answer is:  468 because 22.5g (NH4)2 times 1mole of (NH4)2CO3 divided by 96.11g (NH4)2CO3 equals .234moles of ammonium carbonate (NH4)2CO3. Next multiply .234moles of ammonium carbonate time 2 mole of ammonium (NH4)2 divided by 1mole of ammonium carbonate and your answer will be .468 moles of ammonium.

.234 will give you the amount of moles for ammonium carbonate (NH4)2CO3