Question:

A 3.50 g sample of Al reacts with excess H2SO4...

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What volume of H2 gas is produced at a pressure of 735 mm Hg and a temperature of 22°C?

Here's the chemical reaction equation:

2Al 3H2SO4 → Al2(SO4)3 3H2

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  1. 2Al   &  3H2SO4 → Al2(SO4)3  &   3H2

    find moles of H2, using the equation's mole ratio & molar mass of Al of 26.98g/mole:

    3.50g Al @ 3 mole H2 / (2mole)(26.98g/mol)Al = 0.1946 moles H2

    -------------------------

    find the volume of H2 using

    PV=nRT

    (735Torr)(V) =(0.1946)(62.36Torr-L/mol-K)(295K)

    your answer: V= 4.87 litres

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