A 55.3 kg ice skater is moving at 3.90 m/s when she grabs the loose end of a rope, the opposite end of which?

Question

is tied to a pole. She then moves in a circle of radius 0.798 m around the pole.

(a) Determine the force exerted by the horizontal rope on her arms.

(b) What is the ratio of this force to her weight?

Answer 1

a)  F = m*a = m*V²/R = 55.3*3.9²/.798 =  1054 N

b)  R = F/W = F/mg = 1054/(55.3*9.8) = 4.823