A/a+(3/b) thats a divided by a+3 over b?

Question

A/a+(3/b) thats a divided by a+3 over b?

Answer 1

Easiest if  you write it with the devided by symbol (a line with a dot above and below) instead of the big line between the  whole top and whole bottom.

then like with fractions  flip (recricate) the left sid  (it will look ike this~ (b/(a+3)) and multiply that int both termson th top.

the first term~

[A(a+3)]/ab   then distribute and reduce

(Aa+A3)/ab reduce to (A/b)+(A/ab)

then the second term (the b will cancel out)

3(a+3)

put the together

(A/b)+(3A/ab)+3a+9

Answer 2

I would put more parentheses to be doubly sure your question is answered.

Assuming your question is...

(a/a) + (3/b)

a/a = 1, so

1 + 3/b

1 = b/b so

b/b + 3/b

(b+3)/b

Answer 3

That's what I make it out to be.  The 3/b is clearly one part in itself which is added on to a/a.  Hopefully :D