A ball dropped from a 200 m tall cliff, how long to reach bottom of cliff, how far does it fall after 1st sec?

Question

A ball dropped from a 200 m tall cliff, how long to reach bottom of cliff, how far does it fall after 1st sec?

Answer 1

use this formulas:

g=-9.8m/sec^2

t=V2 - V1

   -----------

    gravity

d=V2 - V1

   ------------

     (2)(g)

Answer 2

Disregarding air resistance, it takes 6.386 seconds to hit the ground. In the first second it falls 4.905 m.

Answer 3

distance = (1/2)(9.81)(t)^2

200 = (0.5)(9.81)t^2

t = sqrt(200 / (0.5*9.81)) = 6.39 seconds.

part 2...

distance = (1/2)a*t^2 = (1/2)(9.81)(1)^2 = 4.91 m

take care,

David