A ball is thrown 200 m upward and then falls. Acceleration=9.8 m/s squared. how long will it be in the air?

Question

i need helppp with this physics problem as well :(

Answer 1

S= 1/2AT^2

200 = 1/2(9.8)t^2

T^2= 200/4.9= 40.81

T= 6.39 seconds  to fall from 200 M to the ground.

or 12.78 seconds if you wish to consider the time it takes for the ball to go up as well as down  

Answer 2

it will be in the air for about 20.5 sec.

Answer 3

Can't really answer this question without knowing how fast it was going in an upward motion.