A battery having an emf of 10.70 V delivers 101 mA when connected to a 60.0 Ohms load.?

Question

Determine the internal resistance of the battery.

Answer 1

Use the loop rule. For a batter, you add the emf to the internal resistance X the current. For the loop rule, use Ohm's law:

V = RI

So you have a 60 ohm load with 101 mA flowing through it, so the voltage is:

V = (60) X (101 x 10^-3) = 6.06 V

So your equation is

- EMF + i * r + V = 0

where i = 101 mA and EMF = 10.7 V. So solve for r to get your answer.

Be sure to draw a circuit diagram to get your signs right. Look in your textbook to see how to do this. I could have a sign error on one of the terms.

David

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