A block of metal absorbs 5017 J of heat when its temperature changes...?

Question

A 4.75 x10^2 g block of metal absorbs 5017 J of heat when its temperature changes from 20.0°C to 30.0°C. Calculate the specific heat of the metal.

_____ J/kg·°C

Answer 1

energy = mass x spec. heat cap. x change in temp

spec. heat cap. = energy / (mass x temp change)

N.B. mass in kilograms

spec. heat cap. = 5017 / (0.475 x 10)

                          1056 J/kg/oC