Question:

A bus leaves at 9.00 am at 50 mph. At 1.00 pm a plane leaves at 300 mph.What time will the plane overtake bus?

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Both bus & plane travel in a straight line and in the same direction.

I need this for my homework assignment. Thanks.

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  1. This question needs more clarification, you see even at 300 m.p.h. an airplane needs to elevate which means there will be distance vertically about 2 minutes more than their estimates roughly a plane escalates vertically, not flat like a bus, but maybe the teacher wants their answer however incorrect it is.


  2. Here's the easy way to think about it.

    1) How far does the bus go before the plane starts?

    Answer:  The bus travels for 4 hours at 50 mph.  So it goes 200 miles.

    2) How long does it take for the plane to make up the 200 mile headstart?

    Answer:  The plane is traveling 250 mph faster than the bus.  200 miles going at 250 mph --> 200/250 = 20/25 = 4/5 hour = 48/60 hours = 48 minutes

    Answer:

    48 minutes later at 1:48 pm

    You can also do this in a slightly longer way:

    Let t be the number of hours after 9am.

    The distance the bus has traveled is 50t

    The distance the plane has traveled is 300(t - 4)

    You want the time when both have traveled the same distance, so equate these and solve for t:

    300(t - 4) = 50t

    300t - 1200 = 50t

    250t - 1200 = 0

    250t = 1200

    t = 1200/250

    t = 4.8

    4.8 hours after 9am is:

    4 hours 48 minutes

    (0.8 = 8/10 = 48/60)

    Answer:

    1:48 pm

  3. at 1:48

  4. x = hours it takes for plane to catch up with bus

    50(4 + x) = 300x

    200 = 250x

    x = 200/250

    x = 0.8 hours or 48 minutes

    Plane will overtake bus at anytime greater than 1:48

    Check:

    48/60hours * 300mph = 240miles

    4.8hours * 50mph = 240miles

  5. After 4 hours bus has travelled 200 miles

    Consider bus to be now at rest and plane travelling at 250 mph

    ie relative speed of plane to bus = 250 mph

    t = 200 / 250 h

    t = 0.8 h

    t = 48 min

    Will overtake at 1:48 pm

  6. Let t be the period of time (from 1.00PM )needed for the plane to overtake the bus

    50*4 + 50*t=300t

    <=>t=0.8 hour

    ==> The plane will overtake the bus at 1.48 PM

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